# CD4052BE DATASHEET PDF

The DMM measurement reads the value 0. It never occurred to me that logic high might be relative to Vdd. I started off with both A and B grounded. This resistance adds to the 1 k external resistance and causes the voltage drop you saw. Home Questions Tags Users Unanswered. Dave Guenther 1 If you need to switch the circuit with only 5v logic you can use an NPN transistor for each input, with a resistor on each collector pulled up to the Vdd level.

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Your input logic to A,B should use the V1 voltage 12v for a high, not 5v. The R2, R3 and R4 all read 0v. Why is there a voltage difference? I started off with both A and B grounded. For example, it shows that with Vdd at 10v you need at least 7v for a high. Sign up or log in Sign up using Google. Home Questions Tags Users Unanswered.

Please let me know if something about this seems incorrect or is I just flat out misinterpreted the use of this chip. Dave Guenther 1 Then send 5v signals into the base of each transistor with a series base resistorand the emitter is connected to GND. If you need to switch the circuit with only 5v logic you can use an NPN transistor for each input, with a resistor on each collector pulled up to the Vdd level.

It cdbs occurred to me that logic high might be relative to Vdd. This resistance adds to the 1 k external resistance and causes the voltage drop you saw. It is most likely implemented with pairs of back to back MOSFETs as the switches, and they have a significant on resistance of ohms or more. Here is a link to the datasheet. Email Required, but never shown. The control signals will be inverted from the base input to the collector output connection. While R1 reads 0. Sign up using Facebook.

So at 12v Vdd you may need about a 9v minimum. Related Posts

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## CD4052BE DATASHEET PDF

Gardagar Your input logic to A,B should use the V1 voltage 12v for a high, not 5v. The DMM measurement reads the value 0. Home Questions Tags Users Unanswered. I dont know why, maybe it fried? It never occurred to me that logic high might be relative to Vdd. This resistance adds to the 1 k external resistance and causes the voltage drop you saw. Also see the switching limitations listed by jms.

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## CD4052BE Datasheet PDF - Texas Instruments

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